What is the maximum wind velocity for a 30° crosswind if the maximum crosswind component for the airplane is 12 knots?

Prepare for the Private Pilot Stage 2 Test. Master key concepts with flashcards and multiple-choice questions, each with hints and explanations. Get ready for success!

To determine the maximum wind velocity for a 30° crosswind when the aircraft has a maximum crosswind component of 12 knots, one needs to use the relationship involving the cosine of the angle of the wind relative to the runway.

In this case, the crosswind component can be calculated using the formula:

[ \text{Crosswind Component} = \text{Wind Velocity} \times \cos(\theta) ]

where (\theta) is the angle of the wind with respect to the runway. For a 30° angle, the cosine value is approximately 0.866.

To find the wind velocity that results in a crosswind component of 12 knots, you set up the equation:

[ 12 \text{ knots} = \text{Wind Velocity} \times \cos(30°) ]

[ 12 = \text{Wind Velocity} \times 0.866 ]

Now, solving for Wind Velocity gives:

[ \text{Wind Velocity} = \frac{12}{0.866} ]

[ \text{Wind Velocity} \approx 13.86 \text{ knots} ]

Since we need to determine the maximum wind velocity and the available choices must include

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy