Given a pressure altitude of 5,000 ft and a headwind of 8 kts, what is the total distance required to land over a 50-foot obstacle?

To determine the correct answer for the total distance required to land over a 50-foot obstacle at a pressure altitude of 5,000 feet with a headwind of 8 knots, it's essential to understand how these variables affect landing performance.

The total distance for landing over an obstacle is influenced by several factors, including aircraft weight, weather conditions, air density (which changes with altitude), and wind components. At a pressure altitude of 5,000 feet, the air density is lower than at sea level. This reduced density increases the landing distance because the aircraft requires a longer distance to achieve the necessary lift and to decelerate effectively.

A headwind of 8 knots aids in slowing down the aircraft as it approaches the landing site. Wind components during landing can significantly affect landing performance; a headwind reduces the ground distance required for landing, making it shorter than it would be with a tailwind or no wind.

In this scenario, the calculations to find the total landing distance for an obstacle include the landing distance required without an obstacle plus any additional distance needed to safely clear the 50-foot object. The specified answer reflects the correct calculations considering these elements.

The figure given in the correct answer—956 feet—accounts for the required adjustments in